-1/4(x-1)^2+1=2x^2-x+3

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Solution for -1/4(x-1)^2+1=2x^2-x+3 equation: 


x in (-oo:+oo)

(-1/4)*(x-1)^2+1 = 2*x^2-x+3 // - 2*x^2-x+3

(-1/4)*(x-1)^2-(2*x^2)+x-3+1 = 0

(-1/4)*(x-1)^2-2*x^2+x-3+1 = 0

x-1/4*(x-1)^2-2*x^2-3+1 = 0

x-1/4*(x-1)^2-2*x^2-3+1 = 0

1/2*x-9/4*x^2+x-3-1/4+1 = 0

3/2*x-9/4*x^2-3-1/4+1 = 0

3/2*x-9/4*x^2-13/4+1 = 0

3/2*x-9/4*x^2-9/4 = 0

3/2*x-9/4*x^2-9/4 = 0

3/2*(x-3/2*x^2-3/2) = 0

x-3/2*x^2-3/2 = 0

DELTA = 1^2-(-3/2*(-3/2)*4)

DELTA = -8

DELTA < 0

3/2 = 0

3/2 = 0

3/2 = 0 // * 2

3 = 0

x belongs to the empty set

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